Factorising Quadratic Expressions When a ≠ 1
Objective:
To learn how to factorise quadratic expressions of the form ax² + bx + c when a is greater than 1.
A quadratic expression looks like:
ax² + bx + c
In the last lesson, we learned how to factorise when a = 1.
Now we will see what to do when a ≠ 1, for example 2x² + 5x + 3.
We start by multiplying the first and last numbers (a × c).
Example:
2x² + 5x + 3
→ a = 2, b = 5, c = 3
→ a × c = 2 × 3 = 6
Now find two numbers that:
multiply to give a × c = 6
add to give b = 5
✅ The numbers are 2 and 3 (why? because they add up to 5 )
Replace the middle term (5x) with two terms using these numbers.
2x² + 2x + 3x + 3
Now we have four terms instead of three.
Group the first two and the last two terms:
(2x² + 2x) + (3x + 3)
Factorise each group separately:
2x(x + 1) + 3(x + 1)
Both groups contain (x + 1), so we can factor that out:
(2x + 3)(x + 1)
✅ Therefore,
2x² + 5x + 3 = (2x + 3)(x + 1)
3x² + 10x + 8
a × c = 3 × 8 = 24
factors of 24
| 2 | 24 |
| 2 | 12 |
| 2 | 6 |
| 3 | 3 |
| 1 |
24 + 1 = 25
12 + 2 = 14
8 + 3 = 11
6 + 4 = 10
Numbers that multiply to 24 and add to 10 → 4 and 6
Replace the middle term (1ox with the the two correct factors 4x and 6x):
3x² + 4x + 6x + 8
Group: (3x² + 4x) + (6x + 8)
Factorise: x(3x + 4) + 2(3x + 4)
Final factors: (x + 2)(3x + 4)
✅ Check: (x + 2)(3x + 4) = 3x² + 10x + 8 ✔
Try to factorise the following:
2x² + 7x + 3
3x² + 8x + 4
4x² + 11x + 6
5x² + 9x + 4
Hint: Multiply a × c, find two numbers that multiply to a×c and add to b, then split the middle term.
When a ≠ 1, multiply a × c first.
Find two numbers whose product is a×c and whose sum is b.
Split the middle term and group terms in pairs.
Factorise each group and take out the common bracket.
Expand to check your final answer.
Next Lesson:
Factorising Quadratic Expressions with Negative or Mixed Signs (e.g. 2x² – 5x – 3)
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